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21 avril 1980 1 21 /04 /avril /1980 11:18

Fungoj

                   







Aj+2 = A 1 x (j + 2)2

      (j + 2)2 = j2+ 4j + 4                                                                                A 1 = 4 - j         

      (j + 2)2 = j + 1 + 4j + 4

      (j + 2)2 = 5j + 5

Aj+2 = (4 - j) x (5j + 5)

Aj+2 = 20j + 20 - 5j2 - 5j

Aj+2 = 20j + 20 - 5(j+1) - 5j

Aj+2 = 20j + 20 - 5j - 5 - 5j

Aj+2 = 10j + 15


 





Bonvenon

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